50 SQL Queries for Database Programmer Interview  

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Demon
(@demonguru)
Member Admin
Joined: 5 years ago
Posts: 41
22/05/2018 3:36 pm  
  1. Display the dept information from department table.

select * from dept;

  1. Display the details of all employees.

select * from emp;

  1. Display the name and job for all employees.

select ename, job from emp;

  1. Display name and salary for all employees.

select ename, sal from emp;

  1. Display employee number and total salary for each employee.

select empno, sal+comm from emp;

  1. Display employee name and annual salary for all employees.

select empno, empname, 12*sal+nvl(comm,0) annualsal from emp;

  1. Display the names of all employees who are working in department number 10.

select ename from emp where deptno=10;

  1. Display the names of all employees working as clerks and drawing a salary more than 3000.

select ename from emp where job=’CLERK’ and sal>3000;

  1. Display employee number and names for employees who earn commission.

select empno, ename from emp where comm is not null and comm>0;

  1. Display names of employees who do not earn any commission.

Select empno, ename from emp where comm is null and comm=0;

  1. Display the names of employees who are working as clerk, salesman or analyst and drawing a salary more than 3000.

select ename from emp where (job=’CLERK’ or job=’SALESMAN’ or job=’ANALYST’) and sal>3000;

(or)

select ename from emp where job in(‘CLERK’,’SALESMAN’,’ANALYST’) and sal>3000;

  1. Display the names of employees who are working in the company for the past 5 years.

select ename from emp where sysdate-hiredate>5*365;

  1. Display the list of employees who have joined the company before 30th June 90 or after 31st dec 90.

select * from emp where hiredate between ‘30-jun-1990’ and ‘31-dec-1990’;

  1. Display current date.

select sysdate from dual;

  1. Display the list of users in your database (using log table).

select * from dba_users;

  1. Display the names of all tables from the current user.

select * from tab;

  1. Display the name of the current user.

show user; 

  1. Display the names of employees working in department number 10 or 20 or 40 or employees working as clerks, salesman or analyst.

select ename from emp where deptno in (10,20,40) or job in (‘CLERK’,’SALESMAN’,’ANALYST’);

  1. Display the names of employees whose name starts with alphabet S.

select ename from emp where ename like ‘S%’;

  1. Display employee names for employees whose name ends with alphabet.

select ename from emp where ename like ‘%S’;

  1. Display the names of employees whose names have second alphabet A in their names.

select ename from emp where ename like ‘_S%’;

  1. Display the names of employees whose name is exactly five characters in length.

select ename from emp where length(ename)=5;

(or)

select ename from emp where ename like '_____';

  1. Display the names of employees who are not working as managers.

select * from emp minus (select * from emp where empno in (select mgr from emp));

(or)

select * from emp where empno not in (select mgr from emp where mgr is not null);

(or)

select * from emp e where empno not in (select mgr from emp where e.empno=mgr) 

  1. Display the names of employees who are not working as SALESMAN or CLERK or ANALYST.

select ename from emp where job not in (‘CLERK’,’SALESMAN’,’ANALYST’);

  1. Display all rows from EMP table. The system should wait after every screen full of information.

set pause on;

  1. Display the total number of employees working in the company.

select count(*) from emp;

  1. Display the total salary being paid to all employees.

select sum(sal)+sum(nvl(comm,0)) from emp;

  1. Display the maximum salary from emp table.

select max(sal) from emp;

  1. Display the minimum salary from emp table.

select min(sal) from emp; 

  1. Display the average salary from emp table.

select avg(sal) from emp;

  1. Display the maximum salary being paid to CLERK.

select max(sal) from emp where job=’CLERK’;

  1. Display the maximum salary being paid in dept no 20.

select max(sal) from emp where deptno=20;

  1. Display the min Sal being paid to any SALESMAN.

select min(sal) from emp where job=’SALESMAN’;

  1. Display the average salary drawn by managers.

select avg(sal) from emp where job=’MANAGER’; 

  1. Display the total salary drawn by analyst working in dept no 40.

select sum(sal)+sum(nvl(comm,0)) from emp where deptno=40;

  1. Display the names of employees in order of salary i.e. the name of the employee earning lowest salary should appear first.

select ename from emp order by sal;

  1. Display the names of employees in descending order of salary.

select ename from emp order by sal desc; 

  1. Display the details from emp table in order of emp name.

select ename from emp order by ename;

  1. Display empno, ename, deptno, and sal. Sort the output first based on name and within name by deptno and within deptno by Sal;

select * from emp order by ename,deptno,sal;

  1. Display the name of the employee along with their annual salary (Sal * 12). The name of the employee earning highest annual salary should appear first.

select ename, 12*(sal+nvl(comm,0)) Annual from emp order by 12*(sal+nvl(comm,0)) desc;

  1. Display name, Sal, hra, pf, da, total Sal for each employee. The output should be in the order of total Sal, hra 15% of Sal, da 10% of sal, pf 5% of sal total salary will be (sal*hra*da)-pf.

select ename,sal,sal*15/100 HRA, sal*5/100 PF, sal*10/100 DA,sal+sal*15/100-sal*5/100+sal*10/100 TOTAL_SALARY from emp

  1. Display dept numbers and total number of employees within each group.

select deptno,count(*) from emp group by deptno;

  1. Display the various jobs and total number of employees with each job group.

select job, count(*) from emp group by job; 

  1. Display department numbers and total salary for each department.

select deptno, sum(sal) from emp group by deptno;

  1. Display department numbers and maximum salary for each department.

select deptno, max(sal),min(sal) from emp group by deptno;

  1. Display the various jobs and total salary for each job.

select job, sum(sal) from emp group by job;

  1. Display each job along with minimum sal being paid in each job group.

select job, min(sal) from emp group by job;

  1. Display the department numbers with more than three employees in each dept.

select deptno, count(*) from emp group by deptno having count(*)>3;

  1. Display the various jobs along with total sal for each of the jobs where total sal is greater than 40000.

select job, sum(sal) from emp group by job having sum(sal)>40000;

  1. Display the various jobs along with total number of employees in each job. The output should contain only those jobs with more than three employees.

select job, count(*) from emp group by job having count(*)>3;

DemonGuru18


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