1

Display the dept information from department table.

ANS

select * from dept;

2

Display the details of all employees.

ANS

select * from emp;

3

Display the name and job for all employees.

ANS

select ename, job from emp;

4

Display name and salary for all employees.

ANS

select ename, sal from emp;

5

Display employee number and total salary for each employee.

ANS

select empno, sal+comm from emp;

6

Display employee name and annual salary for all employees.

ANS

select empno, empname, 12*sal+nvl(comm,0) annualsal from emp;

7

Display the names of all employees who are working in department number 10.

ANS

select ename from emp where deptno=10;

8

Display the names of all employees working as clerks and drawing a salary more than 3000.

ANS

select ename from emp where job=’CLERK’ and sal>3000;

9

Display employee number and names for employees who earn commission.

ANS

select empno, ename from emp where comm is not null and comm>0;

10

Display names of employees who do not earn any commission.

ANS

Select empno, ename from emp where comm is null and comm=0;

11

Display the names of employees who are working as clerk, salesman or analyst and drawing a salary more than 3000.

ANS

select ename from emp where (job=’CLERK’ or job=’SALESMAN’ or job=’ANALYST’) and sal>3000;

(or)

select ename from emp where job in(‘CLERK’,’SALESMAN’,’ANALYST’)and sal>3000;

12

Display the names of employees who are working in the company for the past 5 years.

ANS

select ename from emp where sysdate-hiredate>5*365;

13

Display the list of employees who have joined the company before 30th June 90 or after 31st Dec 90

ANS

select * from emp where hiredate between ‘30-jun-1990’ and ‘31-dec-1990’;

14

Display current date.

ANS

select sysdate from dual;

15

Display the list of users in your database (using log table).

ANS

select * from dba_users;

16

Display the names of all tables from the current user.

ANS

select * from tab;

17

Display the name of the current user.

ANS

show user;

18

Display the names of employees working in department number 10 or 20 or 40 or employees working as clerks, salesman or analyst.

ANS

select ename from emp where deptno in (10,20,40) or job in(‘CLERK’, ‘SALESMAN’, ‘ANALYST’);

19

Display the names of employees whose name starts with alphabet S.

ANS

select ename from emp where ename like ‘S%’;

20

Display employee names for employees whose name ends with alphabet.

ANS

select ename from emp where ename like ‘S%’;

21

Display the names of employees whose names have second alphabet A in their names.

ANS

select ename from emp where ename like ‘_S%’;

22

Display the names of employees whose name is exactly five characters in length.

ANS

select ename from emp where length(ename)=5;
(or)
select ename from emp where ename like ‘_____’;

23

Display the names of employees who are not working as managers.

ANS

select * from emp minus (select * from emp where empno in (selectmgr from emp));
(or)
select * from emp where empno not in (select mgr from emp wheremgr is not null);
(or)
select * from emp e where empno not in (select mgr from emp wheree.empno=mgr)

24

Display the names of employees who are not working as SALESMAN or CLERK or ANALYST.

ANS

select ename from emp where job not in(‘CLERK’,’SALESMAN’,’ANALYST’);

25

Display all rows from EMP table. The system should wait after every screen full of information.

ANS

set pause on;

26

Display the total salary being paid to all employees.

ANS

select sum(sal)+sum(nvl(comm,0)) from emp;

27

Display the maximum salary from emp table.

ANS

select max(sal) from emp;

28

Display the minimum salary from emp table.

ANS

select min(sal) from emp;

29

Display the average salary from emp table.

ANS

select avg(sal) from emp;

30

Display the maximum salary being paid to CLERK.

ANS

select max(sal) from emp where job=’CLERK’;

31

Display the maximum salary being paid in dept no 20.

ANS

select max(sal) from emp where deptno=20;

32

Display the total number of employees working in the company.

ANS

select count(*) from emp;

33

Display the min Sal being paid to any SALESMAN.

ANS

select min(sal) from emp where job=’SALESMAN’;

34

Display the average salary drawn by managers.

ANS

select avg(sal) from emp where job=’MANAGER’;

35

Display the total salary drawn by analyst working in dept no 40.

ANS

select sum(sal)+sum(nvl(comm,0)) from emp where deptno=40

36

Display the names of employees in order of salary i.e. the name of the employee earning lowest salary should appear first.

ANS

select ename from emp order by sal

37

Display the names of employees in descending order of salary.

ANS

select ename from emp order by sal desc;

38

Display the details from emp table in order of emp name.

ANS

select ename from emp order by ename;

39

Display empno, ename, deptno, and sal. Sort the output first based on name and within name by deptno and within deptno by Sal.

ANS

select * from emp order by ename,deptno,sal;

40

Display the name of the employee along with their annual salary (Sal * 12).The name of the employee earning highest annual salary should appear first.

ANS

select ename, 12*(sal+nvl(comm,0)) Annual from emp order by12*(sal+nvl(comm,0)) desc;

41

Display name, Sal, hra, pf, da, total Sal for each employee. The output shoul dbe in the order of total Sal, hra 15% of Sal, da 10% of sal, pf 5% of sal total salary will be (sal*hra*da)-pf.

ANS

select ename,sal,sal*15/100 HRA, sal*5/100 PF, sal*10/100DA,sal+sal*15/100-sal*5/100+sal*10/100 TOTAL_SALARY from emp

42

Display dept numbers and total number of employees within each group.

ANS

select deptno,count(*) from emp group by deptno;

43

Display the various jobs and total number of employees with each job group.

ANS

select job, count(*) from emp group by job;

44

Display department numbers and total salary for each department.

ANS

select deptno, sum(sal) from emp group by deptno;

45

Display department numbers and maximum salary for each department.

ANS

select deptno, max(sal),min(sal) from emp group by deptno;

46

Display the various jobs and total salary for each job.

ANS

select job, sum(sal) from emp group by job;

47

Display each job along with minimum sal being paid in each job group.

ANS

select job, min(sal) from emp group by job;

48

Display the department numbers with more than three employees in each dept.

ANS

select deptno, count(*) from emp group by deptno having count(*)>3;

49

Display the various jobs along with total sal for each of the jobs where total sal is greater than 40000.

ANS

select job, sum(sal) from emp group by job having sum(sal)>40000;

50

Display the various jobs along with total number of employees in each job. The output should contain only those jobs with more than three employees.

ANS

select job, count(*) from emp group by job having count(*)>3;
Facebook
Google+
Twitter
LinkedIn
LEAVE YOUR COMMENTS
http://techhowdy.com/wp-content/uploads/2018/05/Practice-SQL-Question-and-Answers-for-Employee-Table-1024x614.pnghttp://techhowdy.com/wp-content/uploads/2018/05/Practice-SQL-Question-and-Answers-for-Employee-Table-150x150.pngDemonDatabase Programming1 Display the dept information from department table. ANS select * from dept; 2 Display the details of all employees. ANS select * from emp; 3 Display the name and job for all employees. ANS select ename, job from emp; 4 Display name and salary for all employees. ANS select ename, sal from emp; 5 Display employee number and total salary for each employee. ANS select empno, sal+comm...Latest technology news