We have put together list of most frequently used SQL Queries for Database Administrators. Before you start practicing these SQL Queries, use the provided code to Create required Database tables. Fell free to modify these queries to find alternate methods to get the same answers. Use our forum to post questions related to Database programming and one of our admins or registered users will reply back to your query.

All these practice SQL Queries have been tested successfully on Microsoft SQL Server 2014 and Microsoft SQL Server 2017. You would need to run the provided script code in New Query Window, within Microsoft SQL Server Management Studio to Create the Database and Require tables. Under the Code Create Sample Data Section, I have provided the Script Code to create sample data for all tables. Run the this code after you have created the required tables.

Practice these Frequently Asked SQL Queries once before your Interview to get ready to perform them in front of the interviewer.  Please Like, Share and Comment my work to motivate me to produce  more stuff for you guys.

CODE TO CREATE DATABASE AND TABLES

CREATE DATABASE [Practice_SQL]

CREATE TABLE [dbo].[Department](
[Department_ID] [int] NOT NULL,
[Name] [nvarchar](50) NOT NULL,
[Location_ID] [int] NOT NULL
) ON [PRIMARY]

CREATE TABLE [dbo].[Employee](
[Employee_ID] [int] NOT NULL,
[Last_name] [nvarchar](50) NOT NULL,
[First_Name] [nvarchar](50) NOT NULL,
[Middle_name] [nvarchar](50) NOT NULL,
[Job_ID] [int] NOT NULL,
[Manager_ID] [int] NOT NULL,
[HireDate] [date] NOT NULL,
[Salary] [int] NOT NULL,
[Comm] [int] NULL,
[Department_ID] [int] NOT NULL
) ON [PRIMARY]

CREATE TABLE [dbo].[Job](
[Job_ID] [int] NOT NULL,
[Position] [nvarchar](50) NOT NULL
) ON [PRIMARY]

CREATE TABLE [dbo].[Location](
[Location_ID] [int] NOT NULL,
[Regional_Group] [nvarchar](50) NULL
) ON [PRIMARY]

CREATE TABLE [dbo].[Manager](
[Manager_ID] [int] NOT NULL,
[First_Name] [nvarchar](50) NULL,
[Last_Name] [nvarchar](50) NULL,
[Middle_name] [nvarchar](50) NOT NULL,
[Job_ID] [int] NOT NULL,
[HireDate] [date] NOT NULL,
[Salary] [int] NOT NULL,
[Comm] [int] NULL,
[Department_ID] [int] NOT NULL

) ON [PRIMARY]

CODE TO CREATE SAMPLE DATA

INSERT [dbo].[Department] ([Department_ID], [Name], [Location_ID]) VALUES (40, N’ACCOUNTING’, 125)

INSERT [dbo].[Department] ([Department_ID], [Name], [Location_ID]) VALUES (50, N’SALES’, 126)

INSERT [dbo].[Department] ([Department_ID], [Name], [Location_ID]) VALUES (60, N’OPERATIONS’, 127)

INSERT [dbo].[Department] ([Department_ID], [Name], [Location_ID]) VALUES (70, N’RESEARCH’, 128)

INSERT [dbo].[Department] ([Department_ID], [Name], [Location_ID]) VALUES (80, N’FINANCE’, 129)

INSERT [dbo].[Department] ([Department_ID], [Name], [Location_ID]) VALUES (90, N’MARKETING’, 130)

INSERT [dbo].[Department] ([Department_ID], [Name], [Location_ID]) VALUES (100, N’SUPPORT’, 131)

INSERT [dbo].[Employee] ([Employee_ID], [Last_name], [First_Name], [Middle_name], [Job_ID], [Manager_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (1085, N’Smith’, N’Kevin’, N’Q’, 665, 7055, CAST(N’2000-12-17′ AS Date), 800, NULL, 50)

INSERT [dbo].[Employee] ([Employee_ID], [Last_name], [First_Name], [Middle_name], [Job_ID], [Manager_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (1089, N’Fernandez’, N’Joseph’, N’M’, 665, 7044, CAST(N’1998-02-19′ AS Date), 1600, 500, 60)

INSERT [dbo].[Employee] ([Employee_ID], [Last_name], [First_Name], [Middle_name], [Job_ID], [Manager_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (1091, N’Kan’, N’Adrian’, N’J’, 667, 7055, CAST(N’2003-05-30′ AS Date), 1200, 100, 60)

INSERT [dbo].[Employee] ([Employee_ID], [Last_name], [First_Name], [Middle_name], [Job_ID], [Manager_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (1093, N’Cruise’, N’Tom’, N’M’, 667, 7044, CAST(N’2001-01-20′ AS Date), 1100, 50, 40)

INSERT [dbo].[Employee] ([Employee_ID], [Last_name], [First_Name], [Middle_name], [Job_ID], [Manager_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (1095, N’Pitt’, N’Brad’, N’F’, 667, 7021, CAST(N’1999-03-22′ AS Date), 1000, NULL, 50)

INSERT [dbo].[Employee] ([Employee_ID], [Last_name], [First_Name], [Middle_name], [Job_ID], [Manager_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (1097, N’Downey’, N’Robert’, N’J’, 667, 7021, CAST(N’1996-05-14′ AS Date), 900, 600, 40)

INSERT [dbo].[Employee] ([Employee_ID], [Last_name], [First_Name], [Middle_name], [Job_ID], [Manager_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (1099, N’Bale’, N’Christian’, N’H’, 670, 7044, CAST(N’2003-04-22′ AS Date), 850, 100, 40)

INSERT [dbo].[Employee] ([Employee_ID], [Last_name], [First_Name], [Middle_name], [Job_ID], [Manager_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (2001, N’Eastwood’, N’Clint’, N’B’, 670, 7044, CAST(N’2005-02-18′ AS Date), 900, 500, 50)

INSERT [dbo].[Employee] ([Employee_ID], [Last_name], [First_Name], [Middle_name], [Job_ID], [Manager_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (2002, N’Depp’, N’Johnny’, N’A’, 671, 7066, CAST(N’2001-01-20′ AS Date), 950, 300, 40)

INSERT [dbo].[Employee] ([Employee_ID], [Last_name], [First_Name], [Middle_name], [Job_ID], [Manager_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (2003, N’Hanks’, N’Tom’, N’T’, 672, 7066, CAST(N’2013-12-31′ AS Date), 1050, 400, 60)
INSERT [dbo].[Job] ([Job_ID], [Position]) VALUES (665, N’CLERK’)

INSERT [dbo].[Job] ([Job_ID], [Position]) VALUES (667, N’STAFF’)

INSERT [dbo].[Job] ([Job_ID], [Position]) VALUES (670, N’ANALYST’)

INSERT [dbo].[Job] ([Job_ID], [Position]) VALUES (671, N’MANAGER’)

INSERT [dbo].[Job] ([Job_ID], [Position]) VALUES (672, N’PRESIDENT’)
INSERT [dbo].[Location] ([Location_ID], [Regional_Group]) VALUES (125, N’NEW YORK’)

INSERT [dbo].[Location] ([Location_ID], [Regional_Group]) VALUES (126, N’CALFORNIA’)

INSERT [dbo].[Location] ([Location_ID], [Regional_Group]) VALUES (128, N’DALLAS’)

INSERT [dbo].[Location] ([Location_ID], [Regional_Group]) VALUES (129, N’CHICAGO’)

INSERT [dbo].[Location] ([Location_ID], [Regional_Group]) VALUES (130, N’BOSTON’)

INSERT [dbo].[Location] ([Location_ID], [Regional_Group]) VALUES (131, N’TEXAS’)

INSERT [dbo].[Location] ([Location_ID], [Regional_Group]) VALUES (131, N’TEXAS’)
INSERT [dbo].[Manager] ([Manager_ID], [First_Name], [Last_Name], [Middle_name], [Job_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (7021, N’Joe’, N’Root’, N’B’, 671, CAST(N’2000-05-20′ AS Date), 5000, 1000, 50)

INSERT [dbo].[Manager] ([Manager_ID], [First_Name], [Last_Name], [Middle_name], [Job_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (7055, N’James’, N’Anderson’, N’F’, 671, CAST(N’2013-12-25′ AS Date), 10000, 2000, 60)

INSERT [dbo].[Manager] ([Manager_ID], [First_Name], [Last_Name], [Middle_name], [Job_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (7066, N’Ben’, N’Stokes’, N’C’, 671, CAST(N’2018-01-22′ AS Date), 7000, 1500, 60)

INSERT [dbo].[Manager] ([Manager_ID], [First_Name], [Last_Name], [Middle_name], [Job_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (7044, N’Jos’, N’Butler’, N’A’, 671, CAST(N’2016-04-15′ AS Date), 12000, 1900, 50)

INSERT [dbo].[Manager] ([Manager_ID], [First_Name], [Last_Name], [Middle_name], [Job_ID], [HireDate], [Salary], [Comm], [Department_ID]) VALUES (7033, N’Stuart’, N’Broad’, N’N’, 671, CAST(N’2003-03-28′ AS Date), 15000, 1500, 40)

LIST OF QUESTIONS TO PRACTICE

  1. List All The Employee Details
  2. List All The Department Details
  3. List All Job Details
  4. List All The Locations
  5. List Out First Name,Last Name,Salary, Commission For All Employees
  6. List Out Employee_id,Last Name,Department Id For All  Employees And Rename Employee Id As “ID  Of The Employee”, Last Name As “Name Of The Employee”, Department Id As  “Department  ID”
  7. List Out The Employees Annual Salary With Their Names Only.
  1. List the details about “SMITH”
  2. List out the employees who are working in department 50
  3. List out the employees who are earning salary between 500 and 1500
  4. List out the employees who are working in department 40 or 60
  5. Find out the employees who are not working in department 40 or 50
  6. List out the employees whose name starts with “S”
  7. List out the employees whose name start with “S” and end with “H”
  8. List out the employees whose name length is 4 and start with “H”
  9. List out the employees who are working in department 40 and draw the salaries more than 1000
  10. list out the employees who are not receiving commission.
  1. List out the employee id, last name in ascending order based on the employee id.
  2. List out the employee id, name in descending order based on salary column
  3. list out the employee details according to their last_name in ascending order and salaries in descending order
  4. list out the employee details according to their last_name in ascending order and then on department_id in descending order.
  1. How many employees who are working in different departments wise in the organization
  2. List out the department wise maximum salary, minimum salary, average salary of the employees
  3. List out the job wise maximum salary, minimum salary, average salaries of the employees.
  4. List out the no.of employees joined in every month in ascending order.
  5. List out the no.of employees for each month and year, in the ascending order based on the year, month.
  6. List out the department id having atleast four employees.
  7. How many employees in January month.
  8. How many employees who are joined in January or September month.
  9. How many employees who are joined in 1998.
  10. How many employees joined each month in 2003.
  11. How many employees who are joined in April 2003.
  12. Which is the department id, having greater than or equal to 3 employees joined in April 2003.
  1. Display the employee who got the maximum salary.
  2. Display the employees who are working in Sales department
  3. Display the employees who are working as “Clerk”.
  4. Display the employees who are working in “New York”
  5. Find out no.of employees working in “Sales” department.
  6. Update the employees salaries, who are working as Clerk on the basis of 20%.
  7. Delete the employees who are working in accounting department.
  8. Display the second highest salary drawing employee details.
  9. Display the Nth highest salary drawing employee details
  1. List out the employees who earn more than every employee in department 50.
  2. List out the employees who earn more than the lowest salary in department 50.
  3. Find out which department does not have any employees.

Co-Related Sub Queries:

Find out the employees who earn greater than the average salary for their department.

Simple Join

  1. List our employees with their department names
  2. Display employees with their designations (jobs)
  3. Display the employees with their department name and regional groups.
  4. How many employees who are working in different departments and display with department name.
  5. How many employees who are working in sales department.
  6. Which is the department having greater than or equal to 2 employees and display the department names in ascending order.
  7. How many jobs in the organization with designations.
  8. How many employees working in “CALAFORNIA”.

Self Join:

  1. Display the employee details with their manager names.
  2. Display the employee details who earn more than their managers salaries.
  3. Show the no. of employees working under every manager.

Outer Join:

  1. Display employee details with all departments.
  2. Display all employees in sales or operation departments.
  1. List out the distinct jobs in Sales and Accounting Departments.
  2. List out the ALL jobs in Sales and Accounting Departments.
  3. List out the common jobs in Research and Accounting Departments in ascending order.

ANSWERS FOR ABOVE QUESTIONS

ANSWERS FOR SIMPLE QUERY

    1. SQL > Select * from employee;
    2. SQL > Select * from department;
    3. SQL > Select * from job;
    4. SQL > Select * from location;
    5. SQL > Select first_name, last_name, salary, comm from employee;
    6. SQL > Select Employee_ID as “ID of The Employee”, Last_Name as “Name Of The Employee”, Department_ID as “Department ID” from Employee;
    7. SQL > Select Last_Name as “Last Name”, Salary * 12 as “Annual Salary” from Employee

ANSWERS FOR WHERE CONDITIONS
    1. SQL > Select * from employee where last_name = ‘SMITH’;
    2. SQL >Select * from employee where department_id = 50
    3. SQL > Select * from employee where salary between 500 and 1500
    4. SQL >  Select * from employee where Department_ID in (40,60)
    5. SQL > Select last_name, salary, comm, department_id from employee where department_id not in (40,50)

    1. SQL > Select * from employee where last_name like ‘S%’
    2. SQL > Select * from employee where last_name like ‘S%H’
    3. SQL > Select * from employee where last_name like ‘H____’
    4. SQL > Select * from employee where department_id = 40 and salary > 1000
    5. SQL > Select * from employee where comm is Null

ANSWERS FOR ORDER BY CLAUSE

  1. SQL > Select employee_id, last_name from employee order by employee_id
  2. SQL > Select employee_id, last_name, salary from employee order by salary desc
  3. SQL > Select employee_id, last_name, salary from employee order by last_name, salary desc
  4. SQL > Select employee_id, last_name, salary from employee order by last_name, department_id desc

ANSWERS FOR GROUP BY AND HAVING CLAUSE

    1. SQL > Select department_id, count(*) as “Total Employees” from employee group by department_id
    2. SQL > Select department_id, count(*) as “Total Employees” , max(salary) as “Max Salary” , min(salary) as “Min Salary” , avg(salary) as “Avg Salary” from employee group by department_id
    3. SQL > Select job_id, count(*) as “Total Employees” , max(salary) as “Max Salary” , min(salary) as “Min Salary” , avg(salary) as “Avg Salary” from employee group by job_id
    4. SQL > Select A.Month, COUNT(*) As “No Of Employees” from (select MONTH(HireDate) as Month from Employee) A Group by A.Month Order by A.Month

    1. SQL > Select A.Month, A.Year, COUNT(*) As “No Of Employees” from (select MONTH(HireDate) as Month, Year(HireDate) as YEAR from Employee) A Group by A.Month, A.Year Order by A.Month
    2. SQL > Select department_id, count(*) from employee group by department_id having count(*)>=4
    3. SQL >Select A.Month, Count(*) as “No Of Employees” from(select Month(HireDate) as Month from Employee where Month(HireDate) = 1) A Group By A.Month;

    1. SQL > Select Month(HireDate), count(*) from employee group by Month(HireDate) having Month(HireDate) in (1,9)
    2. SQL > Select Year(HireDate), count(*) from employee group by Year(HireDate) having Year(HireDate) = 1998
    3. Select FORMAT([HireDate], ‘MMM’, ‘en-US’) as MONTH, count(*) as “No Of Employees” from employee group by FORMAT([HireDate], ‘MMM’, ‘en-US’)
    4. SQL > Select Year(HireDate) as Year, Month(HireDate) as Month, count(*) as “No. of Employees” from employee where Year(HireDate) = 2003 And Month(HireDate) = 5 group by Year(HireDate), Month(HireDate)

Second Method for Question 11
SQL > Select Year(HireDate) as Year, Month(HireDate) as Month, count(*) as “No. of Employees” from employee group by Year(HireDate), Month(HireDate) Having Year(HireDate) = 2003 And Month(HireDate) = 5

13. SQL > Select Department_ID, Count(*) as “No Of Employees” from employee where Month(HireDate) = 4 and Year(HireDate) = 2003 Group by Department_ID Having Count(*) >= 3

ANSWERS FOR SUB QUERIES

    1. SQL > Select * from employee where salary=(select max(salary) from employee)
    2. SQL > Select * from employee where department_id IN (select department_id from department where name=’SALES’)
    3. SQL > Select * from employee where job_id in (select job_id from job where Position = ‘CLERK’)

    1. SQL > Select * from employee where department_id = (select department_id from department where location_id = (select location_id from [Location] where regional_group =’New York’))
    2. SQL > Select * from employee where department_id = (select department_id from department where [Name] = ‘SALES’ group by department_id)
    3. SQL > Update employee Set salary = (salary + salary*20/100) Where job_id = (select job_id from job where Position=’CLERK’)

    1. SQL > Delete from Employee where Department_ID =(select Department_ID from department where name=’ACCOUNTING’)
    2. SQL > Select * from employee where salary=(select max(salary) from employee where salary <(select max(salary) from employee))
    3. SQL > Select Top 1 Salary from (Select TOP 3 Salary from Employee Order By salary desc) AS emp ORDER BY salary asc

ANSWERS FOR SUB-QUERY OPERATORS: (ALL, ANY<,SOME, EXISTS)

    1. SQL > Select * from employee where salary > all (Select salary from employee where department_id = 50)
    2. SQL > Select * from employee where salary > any (Select salary from employee where department_id = 50)

    1. SQL >Select name from department d where not exists (select last_name from employee e where d.department_id=e.department_id)
    2. SQL > Select employee_id, last_name, salary, department_id from employee e where salary > (select avg(salary) from employee where department_id = e.department_id)

ANSWERS FOR JOINS

    1. SQL > Select employee_id, last_name, name from employee e, department d where e.department_id=d.department_id
    2. SQL > Select employee_id, last_name, Position from employee e, job j where e.job_id=j.job_id
    3. SQL > Select employee_id, last_name, [Name], regional_group from employee e, department d, location l where e.department_id=d.department_id and d.location_id=l.location_id
    4. SQL > Select name, count(*) from employee e, department d where d.department_id=e.department_id group by name
    5. SQL > Select name, count(*) from employee e, department d where d.department_id=e.department_id group by name having name=’SALES’
    6. SQL > Select name, count(*) from employee e, department d where d.department_id=e.department_id group by name having count (*)>= 2 order by name

  1. SQL > Select Position, count(*) from employee e, job j where j.job_id=e.job_id group by Position
  2. SQL > Select regional_group, count(*) from employee e, department d, location l where e.department_id=d.department_id and d.location_id=l.location_id and regional_group=’CALAFORNIA’ group by regional_group

ANSWERS FOR SELF-JOIN

    1. SQL > Select CONCAT( e.First_Name, ‘ ‘, e.Last_name) as “Employee Name”, CONCAT( m.First_Name, ‘ ‘, m.Last_name) as “Manager Name” from employee e, Manager m where e.manager_id = m.Manager_ID
    2. SQL > Select CONCAT( e.First_Name, ‘ ‘, e.Last_name) as “Employee Name”, CONCAT( m.First_Name, ‘ ‘, m.Last_name) as “Manager Name” from employee e, Manager m where e.Salary > m.Salary

  1. SQL > Select M.manager_id, count(*) as “No Of Employees” from employee E, Manager M where E.Manager_ID = M.manager_id group by M.manager_id

ANSWERS FOR OUTER JOIN

    1. SQL > Select E.First_Name, E.Last_name, D.department_id, D.[Name] from Employee E, Department D where E.Department_ID = D.department_id
    2. SQL > Select last_name, d.department_id, d.[Name] as “Dept Name” from employee e, department d where e.department_id = d.department_id and d.department_id in (select department_id from department where name IN (‘SALES’,’OPERATIONS’))

ANSWERS FOR SET OPERATORS

    1. SQL > Select Position from job where job_id in (Select job_id from employee where department_id=(select department_id from department where name=’SALES’)) union Select Position from job where job_id in (Select job_id from employee where department_id=(select department_id from department where name=’ACCOUNTING’))
    2. SQL > Select Position from job where job_id in (Select job_id from employee where department_id=(select department_id from department where name=’SALES’)) union all Select Position from job where job_id in (Select job_id from employee where department_id=(select department_id from department where name=’ACCOUNTING’))

  1. SQL > Select Position from job where job_id in (Select job_id from employee where department_id=(select department_id from department where name=’RESEARCH’)) intersect Select Position from job where job_id in (Select job_id from employee where department_id=(select department_id from department where name=’ACCOUNTING’)) order by Position

BONUS - HOW TO DELETE DUPLICATE ROWS IN SQL

WITH TempEmp (First_name, DuplicateRecordCount)
AS
(
SELECT First_name,ROW_NUMBER() OVER(PARTITION by First_name, Salary ORDER BY First_name)
AS duplicateRecCount
FROM dbo.Employee
)

DELETE FROM TempEmp
WHERE DuplicateRecordCount > 1

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Before you start practicing these SQL Queries, use the provided code to Create required Database tables. Fell free to modify these queries to find alternate methods to get the same answers. Use our forum to...Latest technology news